LibTiff Mailing List
TIFF and LibTiff Mailing List Archive
September 2006
Previous Thread
Next Thread
Previous by Thread
Next by Thread
Previous by Date
Next by Date
Contact
The TIFF Mailing List Homepage
This list is run by Frank Warmerdam
Archive maintained by AWare Systems
Thread
2006.09.17 09:03 "Re: alpha in Grayscale or Palette", by Joris Van Damme
Joris wrote: > As to convertion to Lab, OK, I'm all for that. So now we do indeed > have a 4D space. To make my point, let's encode L, a and b as their > natural float value, and alpha as a float value ranging from 0 to 1. > So, you're saying the difference between L*a*b*alpha (0,0,0,1) (which > is non-transparent black) and (1,0,0,1) (which is non-transparent > almost-black) is equal to the difference between (0,0,0,1) (again > non-transparent black) and (0,0,0,0) (which is total transparency). > > See, we apply weights (full transparent range is equally important as > a difference of 1 in the L range). This is obvious if we pick very bad > weights as we did here. So what are good weights? Full transparent > range is equally important as a difference of 100 in the L range? Or > is it twice as important as a difference of 100 in the L range? Why? I forgot to mention one other reason why I feel this is a challenge. Your 4D model doesn't always apply. Would you say Lab alpha (0,0,0,0) (full transparency) is closer to (100,0,0,1) (non-transparent white) or (50,0,0,1) (non-transparent mid-gray) or (0,0,0,1) (non-transparent black). I think you'll agree full transparency is equally distant from all three. So this is not normal eucledian 4D space. Actually, (0,0,0,0) (full transparency) is equal to (100,0,0,0) (full transparency), which gives rise to the convention to always encoding Lab values (0,0,0) for full transparency in most implementations. So the distance between these two encodings of full transparency is 0. So this is not normal eucledian 4D space. One could be almost tempted to use eucledian distance in a pre-multiplied Lab alpha space, solving this last problem... But still, the arbitrary weights problem stands. Best regards, Joris Van Damme info@awaresystems.be http://www.awaresystems.be/ Download your free TIFF tag viewer for windows here: http://www.awaresystems.be/imaging/tiff/astifftagviewer.html